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Answers
Solution :
From the above question , we can gather that , ∆ ABC is a right angled triangle with angle B = 90° .
Now , it is also given that Angle A = 45° . According to the angle sum criterion , the sum of all the interior angles of any triangle add upto 180° .
So , angle A + angle B + angle C = 180°
=> 90° + 45° + angle C = 180° . Hence , Angle C is 45° . Now , we can observe that angle A = angle C . This shows that ∆ ABC is a right angled isosceles triangle with AB = AC .
Now , let AB = x cm . Applying the Pythagoras theorem here , AB² + AC² = ( 8√2 )²
=> x² + x² = 128
=> 2x² = 128
=> x² = 64
=> x = | ± 8 | = 8 cm .
Answer :
AB = 8 cm
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Step-by-step explanation:
In triangle ABC;
<ABC+ <BAC+ <ACB=180
90+45+ <ACB=180
135+ <ACB=180
<ACB=180-135=45
so triangle ABC is an isoseles triangle where AB=BC
By Pythagoras;
AB^2 +BC^2 =AC^2
AB^2 +AB^2=128
2×AB^2=128
AB^2=64
AB=8