Math, asked by Mohdnoman, 1 year ago

solve the question urgently a and b

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Answered by ishwarsinghdhaliwal
5

(a) \\ 25 \times (5^{\frac{1}{2}}   ) ^{3}  = 5^{p}  \\  {5}^{2}  \times 5 ^{ \frac{3}{2} }  = 5 ^{p}  \\ 5 ^{2 +  \frac{3}{2} }  =5 ^{p}  \\ 5 ^{ \frac{4 + 3}{2} }   = 5 ^{p}  \\ 5 ^{\frac{7}{2}}    = 5 ^{p}  \\  p =  \frac{7}{2} \\  \\  \\  \\ (b) \\ 8 \times (2 ^{ \frac{1}{3} } ) = 2 ^{3p}  \\  {2}^{3 }  \times 2 ^{ \frac{1}{3} }  =  2 ^{3p} \\ 2 ^{3 +  \frac{1}{3} }  =  2 ^{3p} \\ 2 ^{ \frac{9 + 1}{3} }  =  2 ^{3p} \\ 2 ^{ \frac{10}{3} }  =  2 ^{3p} \\  \frac{10}{3}  = 3p \\ p =  \frac{10}{9}
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