solve the question with explanation...
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Answer:
Option (B) is correct
Step-by-step explanation:
i) x²-16 ≤ 4x-11
⇒x²-4x-5≤0
⇒(x+1)(x-5)≤0
⇒x∈[-1,-5]
ii) x²-16>0
⇒x∈(-∞,-4)∪(4,∞)
iii)4x-11>0
⇒x∈(11/4,∞)
Now final answer is intersection of all the three
∴ x∈(4,5]
Option (B) is correct.
Anonymous:
thank you very much for the answer
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