Math, asked by pumabat, 1 year ago

Solve the question with explanation
HCF of 6(x^2-9) and 15(x^3-27)

Answers

Answered by rabs6
1

Answer:

3(x-3)

or

3x -9

Step-by-step explanation:

6 (x^2 - 9)

= 3×2 (x^2 - 3^2) [ a^2-b^2 = (a+b)(a-b)]

= 3×2 ( x-3)(x+3)

15 (x^3 - 27)

= 3×5 ( x^3 - 3^3)

[a3–b3 =(a–b)(a2 + ab + b2 )]

= 3×5 ( x-3) ( x^2 + 3x + 9)

6(x^2-9) = 3×2 (x-3)(x+3)

15(x^3 -27) = 3×5 ( x-3) ( x^2 + 3x + 9)

HCF = 3(x-3)

= 3x-9

Answered by renuhkkohli693
4

Step-by-step explanation:

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