Solve the question with explanation
HCF of 6(x^2-9) and 15(x^3-27)
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Answered by
1
Answer:
3(x-3)
or
3x -9
Step-by-step explanation:
6 (x^2 - 9)
= 3×2 (x^2 - 3^2) [ a^2-b^2 = (a+b)(a-b)]
= 3×2 ( x-3)(x+3)
15 (x^3 - 27)
= 3×5 ( x^3 - 3^3)
[a3–b3 =(a–b)(a2 + ab + b2 )]
= 3×5 ( x-3) ( x^2 + 3x + 9)
6(x^2-9) = 3×2 (x-3)(x+3)
15(x^3 -27) = 3×5 ( x-3) ( x^2 + 3x + 9)
HCF = 3(x-3)
= 3x-9
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