SOLVE THE QUESTION WITH FIGURE
Find the area of the region {(x,y) : y²≤4x , 4x²+4y²≤9}.
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Answer:
From given data in question,
Point of intersection of given two curve y=x
2
and y=−2x+3
x
2
=−2x+3
x=−3,1
Area of shaded region
=∫
−3
1
((−2x+3)−x
2
)dx
=[−x
2
+3x−
3
x
3
]
−3
1
=−(1
2
−3
2
)+3×(1−(−3))−
3
1
3
+3
3
=12+8−
3
28
=
3
32
.
Step-by-step explanation:
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