Question

solve the question. xsquare+2√2x-6=0

Answer 1

${x}^{2} + 2 \sqrt{2} x - 6 = 0$
${x}^{2} - \sqrt{2} x + 3 \sqrt{2} x - 6 = 0$
$x(x - \sqrt{2} ) + 3 \sqrt{2} (x - \sqrt{2} ) = 0$
$(x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0$
$x = \sqrt{2} \: or \: x = - 3 \sqrt{2}$