Question

solve the questions....


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Answer 1

Answer:

Step-by-step explanation:let angle CBO be angle 1

Twice angle 1 +angle ABC=180 [linear pair]

Twice angle 1=180-angle ABC

Angle 1=1/2(180-angle ABC)

Angle 1 =90°-1/2angle ABC -----(1)

Let angle bco be angle 2

Twice angle 2+angle acb=180 [linear pair]

Angle 2 =1/2(180-angle acb

Angle 2 = 90°-1/2angle acb -----(2)

Now adding --(1) &--(2)

Angle CBO+angle BCO+angle BOC=180° [angle sum property]

90°-1/2angle ABC+90°-1/2angle acb+BOC=180

180°-1/2(angle ABC+angle ACB)+BOC=180

-1/2(angle ABC+angle ACB)+BOC=180-180

BOC=1/2(angle B + angle C)

BOC=1/2(180-angle A) ......[a+b+c=180,b+c=180-a]

BOC=90°-1/2angle A

Hence,proved

Hope it helps u mate

Answer 2

Answer:

Step-by-step explanation:

Really knows what time would be good for you to come