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Answers
Answer:
Q3. As ∆ABC similar to ∆PQR
Therefore Angle A = Angle P (By SPST)
So Angle A = 65°
2)Given Data:
ΔABC≅ΔFDE
AB=5cm
∠B=40°
∠A=80°
To find:
DF=?
∠E=?
Solution:
AB≅DF
AB=DF=5cm
DF=5cm
∠A+∠B+∠C=180°
∴∠A=∠F=80°
∠B=∠D=40°
∠C=∠E=?
In ΔFDE,
∠F+∠D+∠E=180°
80°+40°+∠E=180°
120°+∠E=180°
∠E=180°-120°
∠E=60°
∴DF=5cm;∠E=60°
_______________
3)Given Data:
ΔABC≅ΔPQR
In ΔABC, BC=5cm ;∠B=40°;∠C=75°
In ΔPQR, QR=5cm;∠Q=40°;∠R=75°;∠P=65°
To Find:
∠A=?
Solution:
ΔABC≅ΔPQR
∠A= ∠P
∠P=65°(Given)
∠A=65°
Congruence of triangles: Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure.