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number 1 the triangle is shown the distance travelled by the car so you take the formula area of the triangle and take the 1/2×4×20
=40 m/s.
the uniform motion is b to c and the declaration motion c to d
d= u-v/t
=14-20/4
=-6/4
=1.5 m/s^-2
Answered by
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Step-by-step explanation:
A))we will find area under graph for distance. take triangles A and B and find area by 1/2 ×l×b×h .
1)triangle A 1/2×20×4= 40
2)triangle B 1/2×20×4= 40
3) rectangle - l×b= 20×6= 120
Now add 40+40+120=200m
B)) From b to c is uniform motion as its moving with constant velocity.
From c to d is decelerated motion as it velocity is decreasing .
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