Solve the radical equation. 25-40x = x – 10 Which is the true solution? –15 –5 There are no true solutions. Both –5 and –15 and are true solutions.
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Answered by
6
√(25-40x) = x – 10
Square both sides
25 - 40x = x² – 20x + 100
Rearrange
x² +20x + 75 = 0
x² + 5x + 15x + 75 = 0
x(x + 5) + 15(x + 5) = 0
(x + 15)(x + 5) = 0
Either (x + 15) = 0
x = -15
Or
x + 5 = 0
x = -5
Both –5 and –15 and are true solutions
Square both sides
25 - 40x = x² – 20x + 100
Rearrange
x² +20x + 75 = 0
x² + 5x + 15x + 75 = 0
x(x + 5) + 15(x + 5) = 0
(x + 15)(x + 5) = 0
Either (x + 15) = 0
x = -15
Or
x + 5 = 0
x = -5
Both –5 and –15 and are true solutions
Answered by
2
Answer:
Step-by-step explanation:
√(25-40x) = x – 10
Square both sides
25 - 40x = x² – 20x + 100
Rearrange
x² +20x + 75 = 0
x² + 5x + 15x + 75 = 0
x(x + 5) + 15(x + 5) = 0
(x + 15)(x + 5) = 0
Either (x + 15) = 0
x = -15
Or
x + 5 = 0
x = -5
Both –5 and –15 and are true solutions
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