solve the second equation of motion ,,, completely
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Let the distance travelled by the body be “s”.
We know that
Distance = Average velocity ×Time
Also, Average velocity = (u+v)/2
.: Distance (t) = (u+v)/2 × t …….eq.(1)
Again we know that:
v = u + at
substituting this value of “v” in eq.(2), we get
s = (u+u+at)/2 × t
=>s = (2u+at)/2 × t
=>s = (2ut+at^2)/2
=>s = 2ut/2 + at^2/2
or s = ut +1/2 at^2
This is the 2nd equation of motion.
We know that
Distance = Average velocity ×Time
Also, Average velocity = (u+v)/2
.: Distance (t) = (u+v)/2 × t …….eq.(1)
Again we know that:
v = u + at
substituting this value of “v” in eq.(2), we get
s = (u+u+at)/2 × t
=>s = (2u+at)/2 × t
=>s = (2ut+at^2)/2
=>s = 2ut/2 + at^2/2
or s = ut +1/2 at^2
This is the 2nd equation of motion.
tanvigupta2:
thnks.....
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