Math, asked by masreratul962, 1 year ago

Solve the series.
936 126 41 17 50 25 ?

Answers

Answered by anandc607
5

Answer:

Step-by-step explanation:

9^2+3^2+6^2=126

1^2+2^2+6^2=41

4^2+1^2=17

1^2+7^2=50

5^2+0^2=25

2^2+5^2=29

Answered by sharonr
0

The next term in the series 936 126 41 17 50 25 is 29

Solution:

Given, series is 936, 126, 41, 17, 50, 25, ?

We have to solve the series and find the missing number.

Now, as we observe the series, we can write them as.

936,9^{2}+3^{2}+6^{2}=126,1^{2}+2^{2}+6^{2}=41,4^{2}+1^{2}=17,1^{2}+7^{2}=50,5^{2}+0^{2}=25

So, next term term of the series is obtained by sum of squares of digits of previous term.

Now, missing term =  2^{2}+5^{2}=4+25=29

Hence, the next term of the series is 29

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