solve the Shri dhar acharya formula
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hey!!
here is ur answer!!
x^2 - x - 182 = 0
=> x^2 - 14x + 13x -182 = 0
=> x ( x - 14) + 13(x -14) = 0
=> (x+13) (x -14) = 0
(x+13) =0
x = -13
(x-14) = 0
x =14
thus the value of x will be -13 and 14..
hope it helps
here is ur answer!!
x^2 - x - 182 = 0
=> x^2 - 14x + 13x -182 = 0
=> x ( x - 14) + 13(x -14) = 0
=> (x+13) (x -14) = 0
(x+13) =0
x = -13
(x-14) = 0
x =14
thus the value of x will be -13 and 14..
hope it helps
shekhar1257:
use formula
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