Math, asked by nusratsyeda, 2 days ago

solve the simultaneos

2x + 3y = 5
x² + y² = 6x - 4y

Answers

Answered by ITZBRAINLYBOSS07
1

\huge\mathfrak\green{answer}

6x+3y=6xy ; 2x+4y=5xy

⇒ Divide by 3xy ⇒; Divide by xy2

+ x1

=2−−−−(1) ; y2

+ x4

=5−−−−(2)(2) and (1) x3

=3⇒x=1∴ y2

+ 11 =2⇒y=2x=1,y=2 is the solution.

Answered by Anonymous
0

Answer:

Step-by-step explanation:

Solve for the first variable in one of the equation:

Attachments:
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