solve the simultaneos
2x + 3y = 5
x² + y² = 6x - 4y
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6x+3y=6xy ; 2x+4y=5xy
⇒ Divide by 3xy ⇒; Divide by xy2
+ x1
=2−−−−(1) ; y2
+ x4
=5−−−−(2)(2) and (1) x3
=3⇒x=1∴ y2
+ 11 =2⇒y=2x=1,y=2 is the solution.
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Answer:
Step-by-step explanation:
Solve for the first variable in one of the equation:
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