Question

solve the simultaneous equation​

Answer 1

Answer:

x=4

y=12

Step-by-step explanation:

from the first equation we will get

x+y = x^2

from sevond equation

y = 3x

put this value of y in first equation

4x = x^2

x=4

y=12

Answer 2

Answer:

Log (x+y) = 2 logx

Log (x+y) = logx²

==> (X+y) =x²

Y= x²-x ----(1)

Log y = log 3 + logx

Log y = log 3x

==> Y=3x

==> X²-x =3x. (From 1)

X²-4x=0

X(x-4)=0

X=0 or x=4

X≠0 since log 0 is undefined

X=4

Y=3x

Y=3×4

Y=12