Question

solve the simultaneous equation 2x+y=5 3x-y=6​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

We have given two Equations 2x+y= 5 & 3x-y = 6

How to solve ?

step 1: We can solve the above Equations by various ways here ,we solve it through elimination method and then by substitution method.

➞ 2x+y= 5

➞y = 5-2x------(1)

➞ 3x-y= 6

from equation 1

➞3x-(5-2x)=6

➞3x-5+2x=6

➞3x+2x-5=6

➞5x=11

➞x= 11/5

Put X's value into equation 1

➞y= 5-2x

➞y= 5-2(11/5)

➞y= 5-22/5

➞25-22/5

➞y= 3/5

Therefore,x= 11/5 & y = 3/5

Check:-

➞2x+y= 5

➞2(11/5)+3/5

➞22/5+3/5

➞25/5= 5

Alternative Method

By elimination method

➞2x+y=5-----(×3)

➞3x-y= 6------(×2)

New Equation obtained

➞6x+3y=15

➞6x-2y=12

➞$(-)(+)\:(-)$

___________

5y= 3

y= 3/5

➞2x+y=5

➞2x+3/5=5

➞2x=5-3/5

➞2x=25-3/5

➞2x=22/5

➞x= 22/5×1/2

➞x=11/5

Answer 2

Answer:

ǫᴜᴇsᴛɪᴏɴ :-

solve the simultaneous equation 2x+y=5 3x-y=6

ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ :-

2x + y = 5

3x - y = 6

take out the value of x from the first equation

2x + y = 5

=>x = 5-y/2

put the value of x in the second equation

3x - y = 6

= > 3(5-y/2) - y = 6

= > (15 - 3y/2 - y = 6

= > 15 - 3y - 2y = 6 ×2

= > 15 - 5y = 12

= > 15 - 12 = 5y

= > 3/5 = y

now we have find the value of y so we can find the value of x

x=5-y/2

=>5-(3/5) /2

=>25-3/10

=>22/10

=>11/5

so the value of y =3/5

and x = 11/5

Hope it's helpful

Answered by :-

@MissInfinite