Question

solve the simultaneous equation.3a+5b=26;a+5b=12​

Answer 1

Answer:

3a + 5b = 26 ....................(1)

a + 5b = 22 ......................(2)

Subtracting (2) from (1), we get

3a + 5b = 26

a + 5b = 22

____________

2a = 4

____________

⇒ 2a = 4

⇒ a = 4/2

⇒ a = 2

Substituting the value of a = 2 in (2), we get.

a + 5b = 22

⇒ 2 + 5b = 22

⇒ 5b = 22 - 2

⇒ 5b = 20

⇒ b = 20/5

⇒ b = 4

So. the value of a is 2 and the value of b is 4

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Step-by-step explanation:

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Answer 2

Question:

Solve the Following Simultaneous Equation.

3a + 5b = 26;

a + 5b = 12

Step-by-step explanation:

3a + 5b = 26    ___(l)

a + 5b = 12    ___(ll)

Subtracting (ll) from (l)

2a = 14

a = 7

Putting the value of a = 7 in (ll)

a + 5b = 22

⇒ 7 + 5b = 22

⇒ 5b = 22 - 7 = 15

⇒ b = 3