Question

solve the simultaneous equation.
3a+5b=26;a+5b=22​

Answer 1

Answer:

$3a + 5b = 26 \\ a + 5b = 22 \\ we \: can \: solve \: this \: eqn \: by \: using \: eliminatin \: \\ on \: substracting \: these \: eqn \: we \: get \: \: \\ 2a = 4 \\ a = 2 \\ now \:5 b = 26 - 6 \\ b = 4$

Answer 2

Answer:

3a + 5b = 26; .....(I)

a + 5b = 22 .....(II)

Subtracting (II) from (I)

2a = 4

⇒ a = 2

Putting the value of a = 2 in (II)

5b = 22 - 2 = 20

⇒b = 20/5

=4

Thus, a = 2 and b = 4.