Question

solve the simultaneous equation
3a+5b=26;a+5b=22
​

Answer 1

Answer:

3a+5b=26 - a+5b=22

=2a=4

=a=4/2

a=2 put in equation 1st

3x2+5b=26

6+5b=26

5b=26-6

5b=20

b=20/5

b=4

Step-by-step explanation:

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Answer 2

$\large\underline{\sf{Solution-}}$

Given pair of linear equation is

$\rm :\longmapsto\:3a + 5b = 26 - - - (1)$

and

$\rm :\longmapsto\:a + 5b = 22 - - - (2)$

On Subtracting equation (2) from equation (1), we get

$\rm :\longmapsto\:2a = 4$

$\bf\implies \:a = 2$

On substituting the value of a in equation (2), we get

$\rm :\longmapsto\:2 + 5b = 22$

$\rm :\longmapsto\:5b = 22 - 2$

$\rm :\longmapsto\:5b = 20$

$\bf\implies \:b \: = \: 4$

So,

$\bf\implies \:\boxed{ \bf{ \:\begin{gathered}\begin{gathered}\bf\: Solution \: is \: \begin{cases} &\sf{a = 2} \\ \\ &\sf{b = 4} \end{cases}\end{gathered}\end{gathered} \: \: \: \: \: \: \: }}$

Alternative Method :-

Given pair of linear equations is

$\rm :\longmapsto\:3a + 5b = 26 - - - (1)$

and

$\rm :\longmapsto\:a + 5b = 22 - - - (2)$

From equation (2), we have

$\rm :\longmapsto\: 5b = 22 - a$

Substituting this value in equation (1), we get

$\rm :\longmapsto\:3a+ 22 - a = 26$

$\rm :\longmapsto\:2a+ 22 = 26$

$\rm :\longmapsto\:2a = 26 - 22$

$\rm :\longmapsto\:2a = 4$

$\bf\implies \:a = 2$

On substituting the value of a in equation (3), we get

$\rm :\longmapsto\:5b = 22 - 2$

$\rm :\longmapsto\:5b = 20$

$\bf\implies \:b = 4$

So,

$\bf\implies \:\boxed{ \bf{ \:\begin{gathered}\begin{gathered}\bf\: Solution \: is \: \begin{cases} &\sf{a = 2} \\ \\ &\sf{b = 4} \end{cases}\end{gathered}\end{gathered} \: \: \: \: \: \: \: }}$