Question

solve the simultaneous equation 3x + 2y=11 ; 2x+3y=4​

Answer 1

Step-by-step explanation:

solving the problem by elimination method

which gives the value of x=5 and y= -2

Answer 2

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We have,

3x+2y = 11 .... (i)

2x+3y = 4 .... (ii)

From equation (i)

3x+2y = 11

$\implies$ 3x=11-2y

$\implies$ x = $\dfrac{11-2y}{3}$ ... (iii)

Substituting the value of x from equation (iii) in equation (ii), we get

2$\dfrac{11-2y}{3}+3y$ = 4

$\implies\dfrac{22-4y}{3}+3y$ = 4

$\implies\dfrac{22-4y+9y}{3}$= 4

$\implies$22-4y+9y= 12

$\implies$22+5y = 12

$\implies$5y= 12-22

$\implies$5y= -10

$\implies$ y= -$\dfrac{10}{5}$

$\implies$ y= -2

Putting this value of y in equation (iii), we get

x =$\dfrac{11-2(-2)}{3}$

$\implies$x =$\dfrac{11+4}{3}$

$\implies$x =$\dfrac{15}{3}$

$\implies$x =5

Thus, We get the solution as x= 5 and y = -2.