Math, asked by premkaranje6, 8 months ago

Solve the simultaneous equation 3x-y-2=0,2x+y=8.​

Answers

Answered by hinasohail2001
2

Step-by-step explanation:

3x−y−2=0;2x+y=8

Step: Solve3x−y−2=0for y:

3x−y−2+2=0+2(Add 2 to both sides)

3x−y=2

3x−y+−3x=2+−3x(Add -3x to both sides)

−y=−3x+2

−y−1=−3x+2−1(Divide both sides by -1)

y=3x−2

Step: Substitute3x−2foryin2x+y=8:

2x+y=8

2x+3x−2=8

5x−2=8(Simplify both sides of the equation)

5x−2+2=8+2(Add 2 to both sides)

5x=10

5x5=105(Divide both sides by 5)

x=2

Step: Substitute2forxiny=3x−2:

y=3x−2

y=(3)(2)−2

y=4(Simplify both sides of the equation)

Answer:

x=2 and y=4

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Answered by birupakshya17
0

By elimination method

3x-y-2=0

+2x+y-8=0

__________

5x=10

x=2

Then y would be,

2(2)+y=8

y=8-4

y=4

Hope this helps you

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