Question

solve the simultaneous equation 4x+3y-4=0 6x=8-5y​

Answer 1

Answer:

-2, 4

I will tell you how it came.

Step-by-step explanation:

Given;

$4x + 3y - 4 = 0$

$4x + 3y = 4$

Multiply 5 on both sides.

$20x + 15y = 20$

Let this equation will be 1

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$6x = 8 - 5y$

$6x + 5y = 8$

Multiply with 3 on both sides.

$18x + 15y = 24$

Let this equation will be 2

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equation 1 - equation 2

$20x - 15y = 20 \\ 18x - 15y = 24$

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$2x = - 4$

$x = - 2$

Substitute x value in equation 1

$4x + 3y = 4$

$4( - 2) + 3y = 4$

$3y - 8 = 4$

$3y = 12$

$y = 4$

therefore, x = -2, y = 4

Answer 2

Step-by-step explanation:

$4x + 3y - 4 = 0 \: \: \: \: \: \: \: (1) \\ 6x = 8 - 5y \\ 6x + 5y - 8 = 0 \\ now \: we \: get \: to \: do \: cross \: multipliction \\ \frac{x}{ - 24 + 20 } = \frac{y }{ - 24 + 32} = \frac{1}{20 - 18} \\ \frac{x}{ - 4} = \frac{y}{8} = \frac{1}{2 } \\ \frac{x}{ - 4} = \frac{1}{2} \\ x = \frac{ - 4}{2} \\ x = - 2 \\ \frac{y}{8} = \frac{1}{2} \\ y = \frac{8}{2} \\ y = 4 \\ therefor \: the \: soution \: of \: x = - 2 \: and \: y = 4$