Question

solve the simultaneous equation by the method of elimination by equating coefficients 3x-5y+1=0 2x-y+3=0...please...only answer if you know the answer...​

Answer 1

Answer:

3x-5y+1=0 --------------eq1

2x-y+3=0 ---------------eq2

on multiplying by 2 in eq1 and by 3 in eq 2,then

6x-10y+2=0 ---------------eq3

6x-3y+9=0 ----------------eq4

Subtracting eq2 from eq 1

(6x-10y+2)-(6x-3y+9)=0

6x-10y+2-6x+3y-9=0

-10y+3y+2-9=0

-7y-7=0

y=-7/7

y=-1

Put the value of y in eq 1

3x-5y+1=0

3x-5(-1)+1=0

3x+5+1=0

3x+6=0

x= -6/3

x= -2