Math, asked by ojjashemantchavan200, 7 months ago

solve the simultaneous equation y=x/2 2x-y=1​

Answers

Answered by VedankMishra
3

Answer:

One way is to use the method of elimination.

Step 1. Enter the equations.

[1]

y

=

x

2

+

3

x

[2]

y

=

6

2

x

Step 2. Solve for one of the variables in terms of the other.

[2]

y

=

6

2

x

Since this is already done for us, we can go on to the next step.

Step 3. Substitute Equation 2 in Equation 1 and solve for

x

.

6

2

x

=

x

2

+

3

x

x

2

+

5

x

6

=

0

(

x

+

6

)

(

x

1

)

=

0

x

+

6

=

0

and

x

1

=

0

x

=

6

and

x

1

Step4. Substitute each value of

x

in Equation 2

If

x

=

6

,

y

=

6

2

(

6

)

=

6

+

12

y

=

18

If

x

=

1

,

y

=

6

2

(

1

)

=

6

2

y

=

4

Solutions:

x

=

6

,

y

=

18

and

x

=

1

,

y

=

4

Check: Substitute the values of

x

and

y

in Equations 1 and 2.

Check **

1

:

(

-6,18#)

18

=

(

6

)

2

+

3

(

6

)

18

=

36

18

18

=

18

18

=

6

2

(

6

)

18

=

6

+

12

18

=

18

It checks!

</p><p></p><p>4 </p><p>=</p><p>1</p><p>2</p><p>+</p><p>3</p><p>(</p><p>1</p><p>)</p><p> </p><p>4</p><p>=</p><p>1</p><p>+</p><p>3</p><p> </p><p>4</p><p>=</p><p>4</p><p> </p><p></p><p>4</p><p>=</p><p>6</p><p>−</p><p>2</p><p>(</p><p>1</p><p>)</p><p> </p><p>4</p><p>=</p><p>6</p><p>−</p><p>2</p><p> </p><p>4</p><p>=</p><p>4</p><p>

It checks!

Our solutions are correct.

Answered by brainlyAyu
13

Given :- the value of y=x/2

putting the value of y:-

 2x - y = 1   \\ 2x - x \div 2 = 1 \\ (4x - x)  \div 2 = 1 \\ 3x \div 2 = 1 \\ x = 1 \times 2 \div 3 \\ x = 2 \div 3 \\ x = 0.666666667

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