Solve the simultaneous equations
2x + 3y = 8
5x + 2y = 9
Answers
Answered by
13
Answer :-
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Answered by
2
Step-by-step explanation:
Subtract EQn1 from EQn2
5x +2y =9
- 2x +3y =8
(-) (-) (-)
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3x -y =1
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So,y =3x-1
put value of y in EQn 1
2x+3(3x-1)=8
2x+9x-9=8
11x=17
x =17/11
So,y=3*17/11-1
y= 51/11-11/11
y= 40/11
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