Solve the simultaneous equations 4 x + 5 y = − 19 6 x − 3 y = 24 Help this is urgent!!!!
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4x + 5y = −19 -----> eq1
6x − 3y = 24 -------> eq2
eq1 × 3 and eq2 × 5
12x + 15y = -57 ---> eq3
18x - 15y = 120 ---> eq4
add both eq3 and eq4
12x + 18x = 63
30x = 63
x = 21/10
x value in eq1 or eq2
4x + 5y = −19
4(21/10) + 5y = -19
84 + 50y = -190
50y = -190 - 84
y = -274/50
check:
substitute x and y value in eq1 or eq2
4x + 5y = −19
4(21/10) + 5(-274/50) = -19
(84 - 274) / 10 = -19
-190/10 = -19
-19 = -19
LHS = RHS
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hey mate your question is wrong nd plz dont copy above ans that is alos wrong
5×6 = 30 not 18......
nd equation get ans in fractions dont write above ans nd plz check out your question
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