Solve the simultaneous equations (5)
3x+5y=16
2x-y=3
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Step-by-step explanation:
The given equations are
3x−5y=−16 (1)
2x+5y=31 (2)
Note that the coefficients of y in both equations are numerically equal. So, we can eliminate y easily.
Adding (1) and (2), we obtain an equation
5x=15
That is, x=3 (3)
Now, we substitute x = 3 in (1) or (2) to solve for y.
Substituting x = 3 in (1) we obtain, 3(3)−5y=−16
→y=5
Now, (3, 5) a is solution to the given system because (1) and (2) are true when x = 3 and y = 5 as from (1) and (2) we get, 3(3)−5(5)=−16 and 2(3)+5(5)=31.
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