Math, asked by Bishal7507, 1 year ago

solve the simultaneous equations.
5x+4y=4,x-12y=20

Answers

Answered by rvidhyain
14
Hope this helps!

Thank u
Attachments:
Answered by Anonymous
17

5x + 4y = 4 \: equation \: 1 \\  \\ x - 12y = 20  \\  \\ we \: multiply \: 5 \: to \: second \: equation \\  \\ 5x - 60y = 100 \: equation \: 2 \\ now \: we \: will \: solve \: both \: equation \\  \\ \:  \:  5x + 4y = 4 \\  \:  \: 5x - 60y = 100 \\  -  \:  \:  \:  \:  \:  \:  +  \:  \:  \:  \:  \: \:  \:  \:   -  \\  -  -  -  -  -  -  -  -  \\  \:  \: 0 \:  \:  + 64y \:  \:  \:  =  - 96 \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  y =  \frac{ - 96}{64}  =  \frac{ - 32 \times 3}{32 \times 2}  \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: y =  \frac{ - 3}{2}  \\ put \: value \: of \: y \: in \: x - 12y = 20 \\ \:  \:   x - 12( \frac{ - 3}{2} ) = 20 \\  \:  \: x + 18 = 20 \\  \\ x = 20 - 18 = 2 \\  \\ hope \: it \: helpful
Similar questions