Question

solve the simultaneously equation 3x-6/4+3-5y-4/2=5y/2;y-x/4+x/8-7x-5y/3=y-2x

Answer 1

Answer:

Step-by-step explanation:  3x-6/4+3 -5y -4/2  =5y

 by taking L.C.M

                                             =3x-6 +3(4)-2(5y-4)/4 =5y

                                               =3x-6 +12 -10 y +8 =5y(4)=3x  - 10 y + 14   =20 y

      3x - 10 y -20 y =14=3x -30y  =   14 =3(x-10)=14   ;

                                     y-x /4 +    x/8  -7x  - 5 y /3  y -2x =6(y -x) +3 x  - 8 (7x - 5  )y =y -2x

    = 6y -6x + 3 x -56x +  40 y =24 y - 48x

   =46 y -59 x =  24 y -48 x=46 y - 24 y = -48 x +59 x

                                            =22y  = 11 x

                      = 22y -11 x=0

Answer 2

Answer:

3x-6+12-2(5y-4)/4=5y/2

2(3x-6+12-10y+8)=5y×4

2(3x-10y+14)=20y

6x-20y+28=20y

6x-20y-20y= -28

6x-40y= -28

Now divide by 2

3x-20y= -14

y-x/4+x/8 -7x-5y/3=y - 2x

6(y-x)+3x-8(7x-5y)= y-2x

6y - 6x+3x-56x + 40y=24(y-2x)

46y-62x +3x=24y - 48x

46y - 59x = 24y - 48x

-11x = - 22y

- 11x + 22y= 0

divide by 11

- x + 2y = 0_eq2

3x -20y= - 14_eq1

- x + 2y = 0_eq2×3

Now subtract eq1 from eq2

3x - 20y = 14

-3x + 6y= 0

- 14y = -14

y = 1

Now from eq 2

-x + 2y = 0

- x +2×1 =0

- x+2=0

- x = -2

x= 2

y = 1