Question

Solve the stroy sums.
4. If the human body consists of 2/3 of water by mass, find the percentage of water in a person of mass 45 kg. ​

Answer 1

Answer:

Hey There!

Total water present by mass

$= \frac{2}{3}$

$\therefore \: total \: amount \:of \: \: \\ water \: in \: a \: person \\ \\ = \frac{2}{3} \times 45 \\ \\ = \frac{2}{ \cancel{3}} \times \cancel{45} \: \: ^{15} \\ \\ = 15 \times 2 = 30 kg$

Now percentage of water

$= \frac{ \cancel{30} \: \: ^{2} }{ \cancel{45} \: \: ^{3} } \times 100 \\ \\ = \frac{2}{3} \times 100$

=66.6%

$\Large\textsf{Hope \: It \: Helped}$

Answer 2

Answer:

66.6%

Step-by-step explanation:

hope its correct thank you (づ￣ ³￣)づ