solve the sum 3x^2+19x+30 by spillting the middle term of class 9th of chapter polynomial
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Answered by
1
30*3=90
factors of 90=2*5*3*3
3 x2+9x+10x+30
3x(x+3)+10(x+3)
(x+3)(3x+10)
-3, -10/3
please mark it brainliast
Answered by
0
hey mate
given polynomial
=3x²+19x+30
solution:-
=3x²+19x+30
=3x²+10x+9x+30
=3x(x+3)+10(x+3)
=(3x+10)(x+3)
I hopes its helps u
@Abhi.❤❤
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