Question

Solve the sum: A ladder 26 m long reaches a window of a building 24 m
above the ground. Find the distance of the foot of the ladder from the building.

Answer 1

Answer:

Answer = SquareRoot(26^2 - 24^2)

= 10

Step-by-step explanation:

We use the Pythagoras theorem here which says that the longest side's square is equal to the other two side's square's sum.

Answer 2

✤ Question 》

A ladder 26 m long reaches a window of a building 24 m above the ground. Find the distance of the foot of the ladder from the building.

✤ Answer 》

Distance of the foot of the ladder from the building is 10 m

✤ Step by step Explanation 》

As the ladder of length reaches the window 24 m high therefore it makes a right angle triangle as shown in figure.

Therefore Applying Pythagoras Theorem ;

$\large \orange{\pmb{\dag}} \: \: \bf \pink{ {BC}^{2} = {AC}^{2} + {AB}^{2} }$

$:\implies \rm {AB}^{2} = {BC}^{2} - {AC}^{2}$

$:\implies \rm AB {}^{2} = {26}^{2} - {24}^{2}$

$:\implies \rm AB {}^{2} = 676 - 576$

$:\implies \rm AB {}^{2} = 100$

$\large:\implies \bf \blue\maltese \: \: \pink{ \underbrace{ \underline{AB = 10 \: m}}}$

☆ So Distance of the foot of the ladder from the building is 10 meter.