solve the sum by elimination method 2x+3y=32 equation 1. 3x+4y=68 equation 2
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Answer:
y= -40
x= 76
Step-by-step explanation:
2x+3y=32
3x+4y=68
3(2x+3y=32)
2(3x+4y=68)
6x+9y=96
6x+8y=136
equation 1 - equation 2
we get
y= -40
then substitute y value in equation
we get
x=76
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