Question

solve the sum...full method should be done plz..​

Answer 1

Given : 5(2x + 1 ) (3x + 5) ÷ (2x + 1)

Need To Devide : 5(2x + 1 ) (3x + 5) by (2x + 1)

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$\qquad \dag\:\:\bigg\lgroup \sf{ 5(2x + 1 ) (3x + 5) \div (2x + 1) }\bigg\rgroup$

$\large{\gray{\bf Let's \:Devide \:: }}$

$\qquad \longmapsto \sf 5(2x + 1 ) (3x + 5) \div (2x + 1)$

$\qquad \longmapsto \sf \dfrac{5(2x + 1 ) (3x + 5) }{(2x+1)}$

$\qquad \longmapsto \sf \dfrac{5\cancel{(2x + 1 )} (3x + 5) }{\cancel{(2x+1)}}$

$\qquad \longmapsto \bf \bigg( 5(3x+5)\bigg) \qquad \longrightarrow \: Required \:AnswEr \:$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:The \:AnswEr \:is\:\bf{5(3x + 5) }}}}$

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