solve the sum of(3y+1)²
Answers
Answered by
3
(3y+1)²
= (3y)² + 2×3y×1 + 1²
= 9y²+6y+1
= (3y)² + 2×3y×1 + 1²
= 9y²+6y+1
Answered by
0
Hey Friend !
(a+b)² = a²+ 2ab +b²
(3y+1)² = (3y)² + 2 x 3y x 1 + 1²
= 9y² + 6y + 1
= 3(3y² + 2y) +1
(a+b)² = a²+ 2ab +b²
(3y+1)² = (3y)² + 2 x 3y x 1 + 1²
= 9y² + 6y + 1
= 3(3y² + 2y) +1
Similar questions