Question

Solve
The sum of two numbers is 90. One third of the larger number is 9 more than twice the smaller one. What are the numbers?

Note
This is a word problem of equation please do this with variable.​

Answer 1

Step-by-step explanation:

let, smaller no. = x

larger no.= 3*(9+2x)

(because 1/3 of larger no.= 9+2x)

thus, 3*(9+2x)+x= 90

      =) 9+2x+x=90/3

      =)9+2x+x= 30

      =)3x = 30-9

      =)3x= 21

      =) x= 21/3=7

if smaller no.= 7

then larger no.= 3*(9+2*7)

                        = 3*(9+14)

                        =3*23

                         = 63

Answer 2

Answer :

Let the number be x and y .

$\implies\sf{x + y = 90....(i) }$

$\implies\sf{ \frac{1}{3} \times x = 2y +9 }$

$\implies\sf{ \frac{x}{3} - 2y = 9 }$

$\implies\sf{ \frac{x - 6y}{3} }$

$\implies\sf{x - 6y = 27....(ii)}$

$\implies\sf{equation \: 1x - 7y = 90}$

$\implies\sf{equation \: 2 \: \: \: \: x - 6y = 27}$

Therefore , 7y = 63.

$\implies\sf{y = \frac{63}{7} }$

$\implies\sf{y = 9}$

Putting the values of y in equation 1 :

$\implies\sf{x + y = 90} \\ \implies\sf{x + 9 = 90} \\ \implies\sf{x = 90 - 9} \\ \implies\sf{x = 81}$