solve the sum please
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hy friend , here is the answer
in ∆ ABC
angle A = x°
angle B = ( 2x -30° )
angle C = y°
angle A + angle B = 90°
ATQ :
angle A + angle B + angle C = 180°
x + 2x - 30° + y° = 180°
ATQ :
Angle A + angle B = 90°
x° + 2x - 30° = 90°
3x - 30° = 90°
3x = 90° - 30°
3x = 60°
x = 60 / 3
x = 20°
ATQ :
x = 20°
angle A = 20°
angle B = 2x - 30°
= 2(20) - 30°
= 40 - 30°
= 10°
ATQ :
angle A + angle B + angle C = 180°
20° + 10° + y° = 180°
30° + y° = 180°
y° = 180° - 30°
y° = 150°
in ∆ ABC
angle A = x°
angle B = ( 2x -30° )
angle C = y°
angle A + angle B = 90°
ATQ :
angle A + angle B + angle C = 180°
x + 2x - 30° + y° = 180°
ATQ :
Angle A + angle B = 90°
x° + 2x - 30° = 90°
3x - 30° = 90°
3x = 90° - 30°
3x = 60°
x = 60 / 3
x = 20°
ATQ :
x = 20°
angle A = 20°
angle B = 2x - 30°
= 2(20) - 30°
= 40 - 30°
= 10°
ATQ :
angle A + angle B + angle C = 180°
20° + 10° + y° = 180°
30° + y° = 180°
y° = 180° - 30°
y° = 150°
Ritu124103:
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