solve the sum please solve
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[tex]y - 4 \times 3 = y + 3 \times 2 \\ y - 12 = y + 6
Y=18
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Answer:
(4) (y - 4)/2 = (y+3)/3
= (4y - 16)/2 = (y + 3)/3
Cross multiply,
3(4y - 16) = 2(y + 3)
12y - 48 = 2y + 6
10y = 54
y = 5.4 or y = 27/5
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