Question

solve the sums triangle

Answer 1

$\huge{\pink{\underline{\ulcorner{\star \:Solution\: \star}\urcorner}}}$

$\triangle PQR \: and\: right\: angle\: at \:P \\PQ=10\: cm \\ PR =24\: cm$

$\red{\underline{BY\: PYTHAGORAS\: FORMULA\colon}}$

$RQ^{2} = PQ^{2}+ PR^{2}\\\implies \sqrt{10^{2}+24^{2}}\\\implies \sqrt{100+576}\\\implies \sqrt{676}\\\implies 26$

$\triangle ABC\: and\: right\: angle\: at \:C \\AB=25\: cm \\ AC =7\: cm$

$\red{\underline{BY\: PYTHAGORAS\: FORMULA\colon}}$

$BC^{2} = AB^{2} -AC^{2}\\\implies \sqrt{25^{2}+7^{2}}\\\implies \sqrt{625-49}\\\implies\sqrt{576}\\\implies 24$

$\red{\bold{\boxed{ RQ=26\: cm \: and \: BC= 24\: cm}}}$