Question

solve the sums triangle

Answer 1

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️


1️⃣ Right triangle POR

PQ = base = 10cm

PR = Perpendicular = 24cm

QR = hypotenuse = H


use Pythagoras theorem

(QR)² = (PQ)² + (PR)²

(H)² = (10)² + (24)²

${h} = \sqrt{100 + 576} \\ \\ h = \sqrt{676} \\ \\ h = 26$

QR = 26cm


2️⃣ Right triangle ABC

AB = hypotenuse = 25 cm

AC = base = 7cm

BC = perpendicular = P


(BC)² = (AB )² - (AC )²

${p}^{2} = {25}^{2} + {7}^{2} \\ \\ p \: = \sqrt{625 + 49 } \\ \\ p = \sqrt{674}cm \:... or \: ....25.5254$


I HOPE IT WILL HELP You ☺️

Thank you ✌️

Answer 2

Use Pythagoras theorem
..

First ans be


26cm

...And second ans


Be √674 cm