Solve the system. 4x+2y=10. x-y=13
Answers
Answered by
9
Hello friend!!!...Here is ur answer
Given equations are...
4x+2y=10 ------ eq1 and x-y=13 ------13
=> Apply eq 1 + 2 eq 2
then we get..
6x=36
=> x= 6
put the value of x in eq 2
6-y=13
=> y = -7
Hope it will help you
Given equations are...
4x+2y=10 ------ eq1 and x-y=13 ------13
=> Apply eq 1 + 2 eq 2
then we get..
6x=36
=> x= 6
put the value of x in eq 2
6-y=13
=> y = -7
Hope it will help you
ishika3333:
and intelligent virat
Answered by
4
``
Given,
4x + 2y = 10
Take 2 common from both side,
2(2x + y) = 2 (5)
2x + y = 5 ............(1)
x - y = 13 ..............(2)
Now,
Solve both (1) and (2) by elimination,
+ 2x + y = 5
+ 1x - y = 13
________
+ 3x = + 18
x = + 18/3
x = + 6
Put value of x in (2)
6 - y = 13
- y = 13 - 6
- y = 7
y = - 7
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