solve the system of equation 11x+15y+23=0 and 7x-2y-20=0
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Answer:
11X+15Y +23=0----------(1)
7X-2Y-20=0--------------(2)
NOW,
7(11X+15Y+23=0)
77X+105Y +161=0
77X+105Y= -161-------------(3)
11 (7x-2y-20=0)
77X -22Y-220=0
77X-22Y=220----------(4)
SOLVING 4 FROM 3
77X+105Y= -161
77X-22Y= +220
0 +127Y= -381
Y= -381
127
Y=3
THEREFORE PUT THE VALUE OF Y IN EQUATION 3
77X+105Y= -161
77X +105 (3)= -161
77X +315= -161
77X = -161 -315
77X = -476
X= -476
77
X= -6.2
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