Question

Solve the system of equation below
3x+4y=10
6x-2y=40

Answer 1

Answer:

3

$3x + 4y = 10$

$6x - 2y = 40$

Equation 1me 2se aur2me 4se multiply krne pr....

$6x + 8y = 20$

$24x - 8y = 160$

Solve krne pr....

$30x = 180$

$x = 180 \div 30$

$x = 6$

X ki value equation 1 me rakhne pr....

$3x + 4y = 10$

$3 \times 6 + 4y = 10$

$18 + 4y = 10$

$4y = - 8$

$y = - 2$

And finally ur ans is X=6,Y=-2

Hope it help.....

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