solve the system of equation by using the elimination method x+y=7 and 5x+12y=7
Answers
Answered by
1
Answer:
x+y=7 -------------eq1
5x+12y=7 ------------eq2
Multiplying eq1 by 5
5(x+y=7)
5x+5y=35 -----------eq3
solving eq2 and eq3
5x+12y=7
5x+5y=35
(-) (-) (-)
-----------------
7y= (-28)
y= (-4)
substituting the value y in eq1
x+(-4) =7
x= 7+4
x= 11
so. x= 11
y= (-4)
Similar questions