Math, asked by bhartiasar48, 1 month ago

solve the system of equation for x : b²x/a - a²y/b=ab (a+b) and b²x-a²y=2a²b².​

Answers

Answered by jeevankishorbabu9985
1

Answer:

 \small{x:{ \color{cyan}(b^2 x)/a - (a^2 y)/b = a b (a + b), b^2 x - a^2 y = 2 a^2 b^2}}

is the answer

Answered by mathdude500
3

\large\underline{\sf{Solution-}}

Given pair of linear equation is

\rm :\longmapsto\:\dfrac{ {b}^{2} }{a}x - \dfrac{ {a}^{2} }{b}y = ab(a + b)

can be rewritten as

\rm :\longmapsto\:\dfrac{ {b}^{3}x -  {a}^{3}y}{ab} = ab(a + b)

can be further rewritten as

\rm :\longmapsto\:{b}^{3}x -  {a}^{3}y=  {a}^{2}  {b}^{2} (a + b) -  -  - (1)

and

second equation is

\rm :\longmapsto\:{b}^{2}x -  {a}^{2}y=  2{a}^{2}  {b}^{2} -  -  - (2)

Now, we use elimination method to solve these equations.

Multiply equation (2) by b, we get

\rm :\longmapsto\:{b}^{3}x -  b{a}^{2}y=  2{a}^{2}  {b}^{3} -  -  - (3)

Now, Subtracting equation (2) from equation (1), we get

\rm :\longmapsto\: - {a}^{3}y + b{a}^{2}y=  {a}^{2}  {b}^{2} (a + b) - 2 {a}^{2} {b}^{3}

\rm :\longmapsto\: - {a}^{2}y(a -  b)=  {a}^{2}  {b}^{2} (a + b - 2 b)

\rm :\longmapsto\: - y(a -  b)=  {b}^{2} (a  -  b)

\bf\implies \:y =  -  {b}^{2}  -  -  - (4)

Now, Substitute the value of y in equation (2), we get

\rm :\longmapsto\:{b}^{2}x +  {a}^{2} {b}^{2} =  2{a}^{2}  {b}^{2}

\rm :\longmapsto\:{b}^{2}x =  -  {a}^{2} {b}^{2}  +  2{a}^{2}  {b}^{2}

\rm :\longmapsto\:{b}^{2}x = {a}^{2}  {b}^{2}

\bf :\longmapsto\:x = {a}^{2}

Additional Information :-

There are 4 methods to solve this type of pair of linear equations.

1. Method of Substitution

2. Method of Eliminations

3. Method of Cross Multiplication

4. Graphical Method

We prefer here Method of Eliminations :-

To solve systems using elimination, follow this procedure:

The Elimination Method

Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Step 2: Subtract the second equation from the first to eliminate one variable

Step 3: Solve this new equation for other variable.

Step 4: Substitute the value of variable thus evaluated into either Equation 1 or Equation 2 and get the value other variable.

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