Question

solve the system of equation using gauss jordan method. x-y+2z=3, x+2y+3z=5, 3x-4y-5z=-13​

Answer 1

Given :

x-y+2z=3,

x+2y+3z=5,

3x-4y-5z=-13​

To Find  : x , y & z

Solution:

x-y+2z=3,     Eq1

x+2y+3z=5,      Eq2

3x-4y-5z=- 13​     Eq3

Eq1 + Eq2 +  Eq3

=> 5x  - y  = -5

3* Eq1 - 2 * Eq2

=> x - 7y  = - 1

5x  - y  = -5

x - 7y =   - 1  => 5x - 35y  = - 5

=> 34y  = 0

=> y = 0

5x  - y  = -5

=> x = -1

x-y+2z=3,

=> -1 - 0  + 2z = 3

=>  2z = 4

=> z = 2

x = -1

y = 0

z = 2

Learn More:

solve the equation using gauss Jordan method x+2y+6z=443,x+4y+ ...

https://brainly.in/question/16458155

4. a) Solve the following equations by Gauss-Seidel method:10x ...

https://brainly.in/question/22892870

2x+y+4z=12, 8x-3y+2z=20, 4x+11y-z=33 solve by gauss elimination ...

https://brainly.in/question/23496380