Math, asked by princevamsi118, 5 months ago

solve the system of equation x+2y+2z=2 3x-2y-z=5 2x-5y+3z=-4 x+4y+6z=0​

Answers

Answered by dikshikas01
2

answer in the attachment

hope it will help u

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Attachments:
Answered by vivekydv1109
2

Step-by-step explanation:

equation 1 and 2 we get add

x+2y+2z=2

3x-2y-z=5

4x+z=7equation 5

z=7-4x

equation number 3 and 4 we get add

2x-5y+3z=-4

x+4y+6z=0

3x-y+9z=-4 equation 6

equation 5 and 6 we get

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