Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20. A. x = –10, y = 20 B. x = 2, y = 12 C. x = –6, y = 4 D. x = 10, y = 20
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2x + 3y = 40 ...........(1)
-2x + 2y = 20 .........(2)
(1) + (2)
(2x + 3y) + (-2x + 2y) = 40 + 20
5y = 60
y = 12
if 2x + 3y = 40
2x + 3*12 = 40
2x = 40 - 36 = 4
x = 2
answer is b) x = 2 and y = 12
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