Question

Solve the system of equations: 2x + 3y = 8 and 3x - 3y = 12.

Answer 1

Step-by-step explanation:

// Solve equation [2] for the variable  y  

 

 [2]    3y = 2x - 8

 [2]    y = 2x/3 - 8/3

// Plug this in for variable  y  in equation [1]

  [1]    3x - 3•(2x/3-8/3) = 12

  [1]    x = 4

// Solve equation [1] for the variable  x  

  [1]    x = 4  

// By now we know this much :

   x = 4

   y = 2x/3-8/3

// Use the  x  value to solve for  y  

   y = (2/3)(4)-8/3 = 0  

Solution :

{x,y} = {4,0}

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Answer 2

Answer:

Solution :

 {x,y} = {4,0} 

System of Linear Equations entered :

  [1] 3x - 3y = 12   [2] -2x + 3y = -8

Graphic Representation of the Equations :

-3y + 3x = 12 3y - 2x = -8

Solve by Substitution :

// Solve equation [2] for the variable  y  

 

[2] 3y = 2x - 8 [2] y = 2x/3 - 8/3

// Plug this in for variable  y  in equation [1]

  [1] 3x - 3•(2x/3-8/3) = 12   [1] x = 4

// Solve equation [1] for the variable  x  

  [1] x = 4 

// By now we know this much :

  x = 4   y = 2x/3-8/3

// Use the  x  value to solve for  y  

  y = (2/3)(4)-8/3 = 0 

Solution :

 {x,y} = {4,0}