Question

solve the system of equations 3x+3y+3z=1, x+2y=4, 10y+3z=-2, 2x-3y-z=1 ​

Answer 1

The solutions of the equations x+2y+3z=14, 3x+y+2z = 11, 2x + 3y + z = 11 ...

Medium

Solution

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Correct option is D)

let x+2y+3z=14 ------------ (1)

3x+y+2z=11 ---------(2)

2x+3y+z=11 -----------(3)

multiplying eqn (2) by 2 and subtracting eqn(1) from it we get,

=5x+z=8 -------------(4)

again multiplying eqn (2) by 3 and subtracting eqn (3) from it we get,

= 7x+5z=22 ------------(5)

Now multiply eqn (4) by 5 and subtract eqn (5) from it we get

18x=18

∴x=1

substituting the x in eqn (4) we get the value of z as

= 5(1)+z=8

∴z=8−5=3

and substitute x and z in eqn (1) we get

1+2y+3(3)=14

2y=14−1−9=4

∴y=2